Recent content by Emilia27

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    Reviewer FREE CHEGG UNLOCK

    here moment of intertia of semi circle about centroidal axis is taken as Icx =0.11*r^4. Thank you.
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    Reviewer FREE CHEGG UNLOCK

    PROGRAM ====> registration.php ====> <!DOCTYPE html> <html> <head> <title>Registration</title> <style> div { background-color: lightgrey; width: 350px; border: 15px solid green; padding: 50px; margin: 20px; } </style> </head> <body> <div align="center"> <h1 align="center"> My...
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    Reviewer FREE CHEGG UNLOCK

    power supply V = 300 volts capacitence C= 25 uf=25*10^-6 f inductance L= 10mH = 10*10^-3 H Frequency of the LC circuit, (b) when the capacitor connected to inductor ,this circuit behaves as a osscillation circuit, hence the charge in the capacitor changes periodically with...
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    Reviewer FREE CHEGG UNLOCK

    Step 1 - We need to calculate the cost matrix - Plant to Outlet for each product through the different warehouse. This shown below in the screen shot. Next we create the demand table as shown below. Put in the formulas for each cell as shown below. Click on the solver tab and update the...
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    Reviewer FREE CHEGG UNLOCK

    Please paste the chegg link.
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    Reviewer FREE CHEGG UNLOCK

    using System; using System.Collections.Generic; namespace ConsoleApp5 { class Program { static void Main(string[] args) { // Populate the string array with names of members in the Draw string[] names = { "Mr.Smith", "Mr.John"...
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    Reviewer FREE CHEGG UNLOCK

    Ans: {Xi} are iid the likelihood function of Xi's is given by, MLE of ( maximum observation of Xi's ) the likelihood ratio test is given as we reject Ho is, the best critical region is defined as, Given level of significance is
  8. E

    Reviewer FREE CHEGG UNLOCK

    Ans: {Xi} are iid the likelihood function of Xi's is given by, MLE of ( maximum observation of Xi's ) the likelihood ratio test is given as we reject Ho is, the best critical region is defined as, Given level of significance is
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    Reviewer FREE CHEGG UNLOCK

    4]a] Applying conservation of momentum P initial= P final m1u1+m2u2= [m1+m2] V 10,000*2 +20,000*0= [10,000+20,000] V 20,000= 30,000* V V=20,000/ 30,000= 0.67 m/s b] Ke inital= 1/2m1u12+ 1/2m2u22= 1/2*10,000*22+ 1/2*20,000*02= 20,000J KE final= 1/2[m1+m2]V2=1/2[30,000]0.672=6733.5J...
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