Reviewer FREE CHEGG, SCRIBD, STUDOC, AND BARTLEBY THREAD UNLOCK (CLOSED)

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1. Brenda should go about handling this complaint by following several steps, first she should speak politely with the susan and also she should apologize for the miscommunication between them. To make this situation easier that brenda should reimburse the susane amount and get the copier back to the manufacturer and try to find out the problems that susan is facing with the machine. she should also apologize for the miscommunication and for selling her the machine that was not functioning properly.

2. Brenda should have to do several correction to avoid this incidents like brenda should maintained regular communication with the susan, she check from time to time that is susan need training or not about this advanced technology, brenda shouland d also check about the shipment details and make sure that she should rescive the toner or not, brenda should have made regular contact with susan to make sure that everything is functioning properly or not and also make sure that all the item was delivered to her or not that was billed.

3. She should make a system that make her sure that she is maintaining regular communication with her customer and also that system should update her about the functioning of his machine that she delivered to his client.

4. Brenda should make close view to maintain relationship with susan and to make her satisfy. brenda should ready to bear further maintaineence cost of the machine and try to resolve the issues quickly without taking much time , and also provide some other complimentry gift to her to make relationship strong.
 
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First
Question: Calculate the heat of hydrogenation of ethane, C2H4 given the following thermochemical equations: 2 C(graphite) + 3 H2 (g) —> C2H6 (g) ΔHf= - 84.5 kJ/mol 2 C (graphite) + 2 H2 (g) —> C2H4 (g) ΔHf= 52.3 kJ/mol.
Answer:
Step 1
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Step 2
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Second

Question:
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Answer:

Step 1
Given data contains,
ΔHfCO2 (g) = − 393.5 kJ/mol; ΔHfSO2 (g)= −296.8 kJ/mol; ΔHfCS2 (l) = 87.9kJ/molΔHfCO2 (g) = - 393.5 kJ/mol; ΔHfSO2 g= -296.8 kJ/mol; ΔHfCS2 (l) = 87.9kJ/mol
The given chemical reaction is,
CS2(l)+2O2(g)−→CO2(g)+2SO2(g)CS2l+2O2g→CO2g+2SO2g
Step 2
The ∆Hreaction∆Hreaction is calculated as,
∆Hreaction=∑∆Hproducts−∑∆Hreactants∆Hreaction=[−393.5 kJ/mol+2(−296.8 kJ/mol)]−[87.9 kJ/mol]∆Hreaction=−1075 kJ/mol∆Hreaction=∑∆Hproducts-∑∆Hreactants∆Hreaction=-393.5 kJ/mol+2-296.8 kJ/mol-87.9 kJ/mol∆Hreaction=-1075 kJ/mol
The ∆Hreaction∆Hreaction is −1075 kJ/mol-1075 kJ/mol.

Third

Question:
Calculate the ΔH for the reaction: CS2 (l) + 2 O2 (g) —> CO2 (g) + 2 SO2 (g)

Given: ΔHf o CO2 (g) = - 393.5 kJ/mol; ΔHf o SO2 = -296.8 kJ/mol; ΔHf o CS2 (l) = 87.9kJ/mol

Answer:

Step 1
Heat of reaction or enthalpy change (∆H∘rxn)(∆H∘rxn)∆Hrxn∘ is defined as heat released and absorbed during a reaction. It is calculated by the difference of enthalpies of formation of products and enthalpies of formation of reactants.

Note: The given reaction is not balanced but the correct balanced reaction is used in the calculation of enthalpy of reaction.

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