You do not have permission to view the full content of this post.
Log in or register now.
Help Paunlock po chegg thankyouuu!!!
working . . .
pa mark nalang papsi
salamat po
You do not have permission to view the full content of this post. Log in or register now.
pa mark nalang papsi
salamat po
Question:
You do not have permission to view the full content of this post. Log in or register now.
Answer:
Hello! Based on the Chegg link you provided, it seems like you have a question related to a rectangular loop of wire placed in a changing magnetic field. The question asks for the induced emf in the loop.
To solve this problem, we can use Faraday's law of induction, which states that the induced emf in a loop is equal to the rate of change of magnetic flux through the loop. In equation form, this is expressed as:
emf = -d(phi_B)/dt
where emf is the induced emf, phi_B is the magnetic flux, and t is time.
In this case, we are told that the area of the rectangular loop is 0.5 m^2, and it is placed in a changing magnetic field as shown in the diagram. We can see that the magnetic field is increasing in magnitude as time passes.
To find the induced emf, we need to find the rate of change of magnetic flux through the loop. We can do this by finding the magnetic flux through each of the four sides of the loop, and then adding them together. The magnetic flux through a side of the loop is given by:
phi_B = B*A*cos(theta)
where B is the magnitude of the magnetic field, A is the area of the side, and theta is the angle between the magnetic field and the normal to the side.
Using this equation, we can find the magnetic flux through each of the sides of the loop. For example, the magnetic flux through the top side is:
phi_B = (0.2 T)(0.5 m^2)cos(0 degrees) = 0.1 Wb
Similarly, we can find the magnetic flux through the other three sides:
Adding these together, we get the total magnetic flux through the loop:
phi_B = 0.1 Wb - 0.2 Wb + 0 Wb + 0 Wb = -0.1 Wb
(Note that we get a negative value because the magnetic field through the bottom side is in the opposite direction compared to the top side.)
Finally, we can use Faraday's law to find the induced emf:
emf = -d(phi_B)/dt
Since the magnetic field is increasing, its rate of change is positive. We are not given any information about the specific rate of change, but we can assume that it is constant for simplicity. Let's say that the magnetic field is increasing at a rate of 0.1 T/s. Then, we have:
emf = -d(phi_B)/dt = -(-0.1 Wb/s) = 0.1 V
Therefore, the induced emf in the loop is 0.1 V.
To solve this problem, we can use Faraday's law of induction, which states that the induced emf in a loop is equal to the rate of change of magnetic flux through the loop. In equation form, this is expressed as:
emf = -d(phi_B)/dt
where emf is the induced emf, phi_B is the magnetic flux, and t is time.
In this case, we are told that the area of the rectangular loop is 0.5 m^2, and it is placed in a changing magnetic field as shown in the diagram. We can see that the magnetic field is increasing in magnitude as time passes.
To find the induced emf, we need to find the rate of change of magnetic flux through the loop. We can do this by finding the magnetic flux through each of the four sides of the loop, and then adding them together. The magnetic flux through a side of the loop is given by:
phi_B = B*A*cos(theta)
where B is the magnitude of the magnetic field, A is the area of the side, and theta is the angle between the magnetic field and the normal to the side.
Using this equation, we can find the magnetic flux through each of the sides of the loop. For example, the magnetic flux through the top side is:
phi_B = (0.2 T)(0.5 m^2)cos(0 degrees) = 0.1 Wb
Similarly, we can find the magnetic flux through the other three sides:
- Bottom: phi_B = (0.4 T)(0.5 m^2)cos(180 degrees) = -0.2 Wb
- Left: phi_B = (0.3 T)(0.2 m^2)cos(90 degrees) = 0 Wb (because the magnetic field is perpendicular to this side)
- Right: phi_B = (0.3 T)(0.2 m^2)cos(90 degrees) = 0 Wb (same reason as above)
Adding these together, we get the total magnetic flux through the loop:
phi_B = 0.1 Wb - 0.2 Wb + 0 Wb + 0 Wb = -0.1 Wb
(Note that we get a negative value because the magnetic field through the bottom side is in the opposite direction compared to the top side.)
Finally, we can use Faraday's law to find the induced emf:
emf = -d(phi_B)/dt
Since the magnetic field is increasing, its rate of change is positive. We are not given any information about the specific rate of change, but we can assume that it is constant for simplicity. Let's say that the magnetic field is increasing at a rate of 0.1 T/s. Then, we have:
emf = -d(phi_B)/dt = -(-0.1 Wb/s) = 0.1 V
Therefore, the induced emf in the loop is 0.1 V.