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Answer

1.Jose rizal was born in calamba, Laguna on June 19 ,1861.to a well-to-do family he studied at the Jesuit and the municipal in Manila. he won many literary honours and prices .we obtained a bachelor of arts degree with highest honours in 1877 .

1.at the age of 2 rizal could already write and read

2.rizal also joined such type of ******** where he won one-third of the grand prize with ticket number 9736 .

3.he mastered 22 languages

4 .rizal could show too much sarcasm because of his love for his country .



5.rizal wasone of the few recognised "renaissance man "in the world. three animal species were named after result

6titled the soil and planted trees corn,abaca and many fruit trees he practiced his profession as physician and eye surgeon .he constructed residential and little hospital houses. he also assistance to the beautification of the public square.

trial

1.on December 6, 1896 the trial of Dr Jose rizal by Spanish military court for sedition rebellion and conspiracy begin

2.this leads to his execution and martyrdom. 3.this result was executed on December 30 ,1896 in bagumbayan renamed rizal park in his memory.

death

1.rizal death in December 31, 1896 changed the Philippines.

2. the filipinos were truly affected by his death 3.in a sense that they were urged to start a revolution against the Spanish government to gain control of the Philippines.

3.rizal is the national hero of Philippines. he was the one who led the Philippines to start a revolution against the Spanish government to attain freedom and to gain control of the country. though that other filipinos were motivated to get that freedom they started many revolts against the Spanish government.
 
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Answer 1

Given

L = 120m

g1 = +2%

x = 54m

Elevation at 54m = 27.79m

P.C Elevation = 27.12 m

Tangent Elevation at 54m = 27.12 + (0.02 x 54) = 28.2 m

Tangent offset at 54m = 28.2 - 27.79 = 0.41 m

y=\frac{x^{2}A}{200L}


A = g2 - g1

0.41 = ( 54 x 54 ) (A / (200 x 120)

A = 3.37 = 3.4

g2 - g1 = 3.4

g2 = 2 + 3.4 = + 5.4%

Elevation of P.I = 27.12 + (0.02 x 60) = 28.32 m

Elevation of P.T = 28.32 + (0.054 x 60 ) = 31.56m

Highest point on curve = x = L g1 / A = 120 x 2 /3.4 = 70.59 m

Station of pipe culverts be located at highest point of the curve

Answer 2

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Answer 3

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