16. Construct a characteristic curve for a typical screen-film combination and carefully label the axes.
17. An x-ray examination of the heart taken at 100 cm SID shows a cardiac silhouette measuring 13 cm in width. If the OID distance is estimated at 15 cm, what is the actual width of the heart?
18. The subject contrast of a thorax is 5.3. Image recep- tor contrast is 3.2. What is the radiographic contrast?
16. A characteristic curve, also known as an H & D curve (Hurter and Driffield curve), is a graphical representation of the relationship between the exposure (intensity or dose of radiation) and the resulting optical density on a film. Here's an example of how a characteristic curve for a typical screen-film combination might look:
On the y-axis, we have the optical density (OD), which represents the degree of blackness or darkness on the film. It usually ranges from 0 (completely transparent) to 4 (completely opaque).
On the x-axis, we have the logarithm of the exposure (logE), which represents the amount of radiation exposure to the film. The logarithmic scale is used because it allows for a wider range of exposure values to be plotted on a manageable scale.
The curve starts at the lower left corner of the graph, indicating low exposure and low optical density. As the exposure increases, the optical density increases, resulting in a steeper slope of the curve. At a certain point, the curve starts to level off, indicating a saturation point where further increases in exposure do not significantly increase the optical density.
The position and shape of the characteristic curve can vary depending on the screen-film combination used.
17. To calculate the actual width of the heart, we need to take into account the object-to-image receptor distance (OID). The actual width (AW) can be calculated using the formula:
AW = (IS - OID) / SID
Where IS is the measured width on the image, OID is the object-to-image receptor distance, and SID is the source-to-image receptor distance.
In this case, the measured width of the cardiac silhouette is 13 cm, the OID distance is estimated at 15 cm, and the SID is 100 cm. Plugging these values into the formula:
AW = (13 cm - 15 cm) / 100 cm = -0.02 cm
The result is negative because the actual width is smaller than the measured width on the image. Therefore, the actual width of the heart is approximately 0.02 cm smaller than the measured width.
18. Radiographic contrast is calculated by subtracting the image receptor contrast from the subject contrast. In this case:
Radiographic Contrast = Subject Contrast - Image Receptor Contrast
= 5.3 - 3.2
= 2.1
Therefore, the radiographic contrast is 2.1.