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#include <stdio.h>
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
if (num == 0) {
printf("Zero\n");
} else if (num % 2 == 0) {
printf("Even\n");
} else {
printf("Odd\n");
}
return 0;
}
num
to store the user input.printf
function and read the input using the scanf
function.if-else
statement to check the value of num
:num
is 0, we print "Zero" using printf
.num % 2
is 0, we print "Even".how about this poTo solve this problem in the C language, you can use the modulo operator (%) to determine if a number is even or odd. If the remainder of the number divided by 2 is 0, then it is even. Otherwise, it is odd.
Here's a C program that implements this logic:
C:#include <stdio.h> int main() { int num; printf("Enter an integer: "); scanf("%d", &num); if (num == 0) { printf("Zero\n"); } else if (num % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } return 0; }
Explanation:
1. We declare an integer variablenum
to store the user input.
2. We prompt the user to enter an integer using theprintf
function and read the input using thescanf
function.
3. We use anif-else
statement to check the value ofnum
:
- Ifnum
is 0, we print "Zero" usingprintf
.
- Ifnum % 2
is 0, we print "Even".
- Otherwise, we print "Odd".
4. Finally, we return 0 to indicate successful program execution.
You can compile and run this program to see the desired output based on the user's input.
To solve this problem in the C language, you can use a combination of character comparison and conditional statements.how about this po
C language
2. Tell Me Your Gender...or Not.
Ask the user to input a character for their gender.
Print "Male" if the input is M or m, "Female" if the input is F or f.
If the input is not one of those mentioned, print "Prefer not to say".
Sample Output 1
Enter a character: M
Male
Sample Output 2
Enter a character: F
Female
Sample Output 3
Enter a character: a
Prefer not to say
#include <stdio.h>
int main() {
char gender;
printf("Enter a character: ");
scanf(" %c", &gender);
if (gender == 'M' || gender == 'm') {
printf("Male\n");
} else if (gender == 'F' || gender == 'f') {
printf("Female\n");
} else {
printf("Prefer not to say\n");
}
return 0;
}
gender
to store the user input.printf
function and read the input using the scanf
function. Note the space before %c
in the scanf
statement, which is used to skip any leading whitespace characters.if-else
statement to check the value of gender
:gender
is M
or m
, we print "Male" using printf
.gender
is F
or f
, we print "Female".C languageTo solve this problem in the C language, you can use a combination of character comparison and conditional statements.
Here's a C program that implements this logic:
C:#include <stdio.h> int main() { char gender; printf("Enter a character: "); scanf(" %c", &gender); if (gender == 'M' || gender == 'm') { printf("Male\n"); } else if (gender == 'F' || gender == 'f') { printf("Female\n"); } else { printf("Prefer not to say\n"); } return 0; }
Explanation:
1. We declare a character variablegender
to store the user input.
2. We prompt the user to enter a character using theprintf
function and read the input using thescanf
function. Note the space before%c
in thescanf
statement, which is used to skip any leading whitespace characters.
3. We use anif-else
statement to check the value ofgender
:
- Ifgender
isM
orm
, we print "Male" usingprintf
.
- Ifgender
isF
orf
, we print "Female".
- Otherwise, we print "Prefer not to say".
4. Finally, we return 0 to indicate successful program execution.
You can compile and run this program to see the desired output based on the user's input.
To solve this problem in the C language, you can obtain two integers from the user and then compute their sum. After that, you can check if the sum is positive, negative, or zero using conditional statements.C language
Positive, Negative, or Zero?
by CodeChum Admin
Ask the user to input two integers and then compute for their sum.
Check and print on the next line if the sum is positive, negative, or zero.
Sample Output 1
Enter first number: 6
Enter second number: 4
Positive
Sample Output 2
Enter first number: -45
Enter second number: 41
Negative
Sample Output 3
Enter first number: 0
Enter second number: 0
Zero
#include <stdio.h>
int main() {
int num1, num2, sum;
printf("Enter first number: ");
scanf("%d", &num1);
printf("Enter second number: ");
scanf("%d", &num2);
sum = num1 + num2;
if (sum > 0) {
printf("Positive\n");
} else if (sum < 0) {
printf("Negative\n");
} else {
printf("Zero\n");
}
return 0;
}
num1
and num2
to store the user input, and sum
to store their sum.printf
function and read the input using the scanf
function.printf
function and read the input using the scanf
function.num1
and num2
and store it in the sum
variable.if-else
statement to check the value of sum
:sum
is greater than 0, we print "Positive" using the printf
function.sum
is less than 0, we print "Negative".sum
is equal to 0, we print "Zero".c languageTo solve this problem in the C language, you can obtain two integers from the user and then compute their sum. After that, you can check if the sum is positive, negative, or zero using conditional statements.
Here's a C program that implements this logic:
C:#include <stdio.h> int main() { int num1, num2, sum; printf("Enter first number: "); scanf("%d", &num1); printf("Enter second number: "); scanf("%d", &num2); sum = num1 + num2; if (sum > 0) { printf("Positive\n"); } else if (sum < 0) { printf("Negative\n"); } else { printf("Zero\n"); } return 0; }
Explanation:
1. We declare three integer variables:num1
andnum2
to store the user input, andsum
to store their sum.
2. We prompt the user to enter the first number using theprintf
function and read the input using thescanf
function.
3. We prompt the user to enter the second number using theprintf
function and read the input using thescanf
function.
4. We compute the sum ofnum1
andnum2
and store it in thesum
variable.
5. We use anif-else
statement to check the value ofsum
:
- Ifsum
is greater than 0, we print "Positive" using theprintf
function.
- Ifsum
is less than 0, we print "Negative".
- Ifsum
is equal to 0, we print "Zero".
6. Finally, we return 0 to indicate successful program execution.
You can compile and run this program to see the desired output based on the user's input.
To solve this problem in the C language, you can obtain three decimal values from the user and then compute their sum. After that, you can check the sum against different ranges to determine the corresponding wealth level.c language
Let's Get Rich!
by CodeChum Admin
Ask the user to input three decimal values which represents the money they earned per year, in three years. Add them all up.
If it is below 200,000, print "average".
If it is 200,000 and above but below 400,000, print "rich".
If it is 400,000 and above but below 600,000, print "super rich".
If it is 600,000 and above, print "crazy rich" on the next line.
Sample Output 1
Enter decimal value 1: 150000.15769
Enter decimal value 2: 20000.57935
Enter decimal value 3: 10000.5789
average
Sample Output 2
Enter decimal value 1: 149999.27
Enter decimal value 2: 10000.1576
Enter decimal value 3: 80000.25
rich
Sample Output 3
Enter decimal value 1: 356123.123
Enter decimal value 2: 20000.872
Enter decimal value 3: 23876.005
super rich
#include <stdio.h>
int main() {
float value1, value2, value3, sum;
printf("Enter decimal value 1: ");
scanf("%f", &value1);
printf("Enter decimal value 2: ");
scanf("%f", &value2);
printf("Enter decimal value 3: ");
scanf("%f", &value3);
sum = value1 + value2 + value3;
if (sum < 200000) {
printf("average\n");
} else if (sum >= 200000 && sum < 400000) {
printf("rich\n");
} else if (sum >= 400000 && sum < 600000) {
printf("super rich\n");
} else {
printf("crazy rich\n");
}
return 0;
}
value1
, value2
, and value3
to store the user input, and sum
to store their sum.printf
function and read the input using the scanf
function.printf
function and read the input using the scanf
function.C languageTo solve this problem in the C language, you can obtain three decimal values from the user and then compute their sum. After that, you can check the sum against different ranges to determine the corresponding wealth level.
Here's a C program that implements this logic:
C:#include <stdio.h> int main() { float value1, value2, value3, sum; printf("Enter decimal value 1: "); scanf("%f", &value1); printf("Enter decimal value 2: "); scanf("%f", &value2); printf("Enter decimal value 3: "); scanf("%f", &value3); sum = value1 + value2 + value3; if (sum < 200000) { printf("average\n"); } else if (sum >= 200000 && sum < 400000) { printf("rich\n"); } else if (sum >= 400000 && sum < 600000) { printf("super rich\n"); } else { printf("crazy rich\n"); } return 0; }
Explanation:
1. We declare three float variables:value1
,value2
, andvalue3
to store the user input, andsum
to store their sum.
2. We prompt the user to enter the first decimal value using theprintf
function and read the input using thescanf
function.
3. We prompt the user to enter the second decimal value using theprintf
function and read the input using thescanf
function.
4.
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ano course mo TS? CSIT-122 ba subject code nito?Code chump kasi gamit dapat walang kahit isang mali ahhaha
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